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Transform directory with arbitrary XML files
Added by Anonymous over 16 years ago
Legacy ID: #4497174
Legacy Poster: Dominik Schadow (xml-security)
Hi there, I'm using Ant to generate about 50 HTML from XML files (with the same XSL)
- Saxon-B 8.9 for Java. At the moment I'm using this for every XML file: <java
fork="true"
classname="net.sf.saxon.Transform"> <classpath
refid="saxon8.classpath"/> <arg
value="-o"/> <arg
value="${helpBasics}\sample.html"/> <arg
value="${xmlBasics}\sample.xml"/> <arg
value="${helpXsl}"/> </java> The name of the XML
file determines the name of the HTML file (they should be the same). Is there a
possibility to simplify these calls? My idea is to provide the source directory and the
target directory and Saxon takes all available XML files and creates the HTML files. Is
there any build in function to do that (does Transform accept directories) or do I have
to write my own? Thanks for the info Regards, dos
Legacy ID: #4497246
Legacy Poster: Michael Kay (mhkay)
Doing this via 50 invocations from the command line looks very inefficient - with a
fork, I think you're loading a new Java VM each time which will dwarf the cost of the
transformation. I don't know enough about the Ant xslt task to know whether that will be
better, but I would guess so. Saxon does have a command line option to process a whole
directory but it's not especially flexible; you could also consider processing all the
input in a single transformation by reading the input files using the collection()
function.
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