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puzzling regex problem
Added by Anonymous over 18 years ago
Legacy ID: #3352138
Legacy Poster: xristy (xristy)
I'm using saxonB 8.5.1. I have data like: <outline:name>Volume KA -
1</outline:name> and: <outline:name>Volume PHA -
14</outline:name> I am using: <xsl:analyze-string
select="." regex="vol.\s([0-9][0-9])"
flags="i"> <xsl:matching-substring>
<outline:vol> <xsl:value-of
select="regex-group(1)"/> </outline:vol>
</xsl:matching-substring> </xsl:analyze-string> The problem
that I have is that no matter what contortions I go to with the regex, regex-group(1) is
always the only or last digit - that is I get "1" for
"1" and "0" for "10" and
"1" for "11". I've tried
regex="vol.\s*([0-9]+)" and
regex="vol.\s([0-9]{{2}}|[0-9]{{1}})" The last in a fit of
desparation -;) As I understand the specs the first choice dominates if it matches, but
in all cases the result element is just a single digit:
<outline:vol>1</outline:vol> If I use an expression like:
regex="vol.\s([0-9]{{2}})" I indeed get just the two digit cases:
<outline:vol>22</outline:vol> and so on. I'm beyond puzzled
about how to use the XSL regex feature. Thanks in advance for any help with this problem
Legacy ID: #3352167
Legacy Poster: Michael Kay (mhkay)
With this regex: vol.\s([0-9][0-9]) and this input Volume PHA - 14 the matching
is as follows: "vol" matches "Vol" . matches
"ume PHA - 1" \s* matches nothing [0-9][0-9]* matches
"4" Perhaps you meant \s+, requiring at least one space before the
final number. Michael Kay http://www.saxonica.com/
Legacy ID: #3352214
Legacy Poster: xristy (xristy)
Thanks. As it turns out, for my purposes:
regex="vol.?([0-9][0-9])" may be more robust since there might not
be a \s before the number.
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