Forums » Help »
Invoke Transformation by specifying template
Added by Anonymous almost 19 years ago
Legacy ID: #3172380
Legacy Poster: Theo Gülcher (gulcher)
I am trying the Up-conversion using XSLT 2.0 GEDCOM example. I want to make the
Stage One conversion from a GEDCOM file to RAW XML from Java: My code is: private static
FileOutputStream transform() { FileOutputStream out = null; try { TransformerFactory
factory = TransformerFactory.newInstance(); StreamSource xsl = new
StreamSource("gedcom2rawxml.xsl"); Templates templates =
factory.newTemplates(xsl); Transformer transformer = templates.newTransformer(); out =
new FileOutputStream("family.xml"); File in = new
File("family.ged");
transformer.setParameter("input", readFile(in)); StreamResult result =
new StreamResult(out); StreamSource source = new StreamSource(sourcePath);
transformer.transform(source, result); net.sf.saxon.Transform t = new
net.sf.saxon.Transform(); t. } catch (TransformerConfigurationException e) {
e.printStackTrace(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch
(TransformerException e) { e.printStackTrace(); } catch (IOException e) {
e.printStackTrace(); } return out; } When I run this I get: Error on line 1 of
file:/g:/family/myfamily.ged: SXXP0003: Error reported by XML parser: Document root
element is missing. net.sf.saxon.trans.DynamicError: org.xml.sax.SAXParseException:
Document root element is missing. Can someone help me by getting this textfile to
transform? Thanks in advance! Theo.
Legacy ID: #3172427
Legacy Poster: Michael Kay (mhkay)
This stylesheet uses a named template as its entry point, and has no source
document. From the command line you can run this by specifying "-it
main" and not specifying a source file. From JAXP (or JAXP as extended by Saxon
to handle XSLT 2.0) you specify the initial template using
((Controller)transformer).setInitialTemplate(initialTemplate) and you can supply
"null" as the source parameter to the transform() method. If I
remember rightly the stylesheet expects the input parameter to be a relative URI, I'm
not sure what readFile() does but it's possible you're supplying the contents of the
file rather than its name. Michael Kay
Please register to reply
.