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Should fn:transform in SaxonCS support XSLT version 4?

Added by Martin Honnen about 3 years ago

I am trying to run fn:transform from XQuery 4 in SaxonCS, calling an XSLT 4 stylesheet:

xquery version "4.0";

declare namespace output = "http://www.w3.org/2010/xslt-xquery-serialization";

declare option output:method 'xml';

let $xslt := 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="4.0"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="#all"
  xmlns:ext="http://example.com/mf"
  extension-element-prefixes="ext"
  expand-text="yes">
  
  <xsl:template name="ext:sequence">
    <xsl:param name="select" as="item()*"/>
    <xsl:param name="separator" select="''"/>
    <xsl:for-each select="$select" separator="{{$separator}}">
      <xsl:sequence select="."/>
    </xsl:for-each>
  </xsl:template>

</xsl:stylesheet>,

$seq := ('a', 'b', <c/>, 'd', 'e', <f/>, <g/>,  'h')

return <e>{transform(map { 'stylesheet-node' : $xslt, 'initial-template' : QName('http://example.com/mf', 'sequence'), 'template-params' : map { QName('', 'select') : $seq }, 'xslt-version' : 4.0})?output}</e>

I get the error: "The transform option xslt-version is higher than the XSLT version supported by this processor".

Is that expected? Is there so far no support in fn:transform to use XSLT 4?


Replies (5)

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RE: Should fn:transform in SaxonCS support XSLT version 4? - Added by Martin Honnen about 3 years ago

If I don't specify the xslt-version option, as shown below, I get told "Attribute xsl:for-each/@separator is allowed only if XSLT 4 is enabled".

xquery version "4.0";

declare namespace output = "http://www.w3.org/2010/xslt-xquery-serialization";

declare option output:method 'xml';

let $xslt := 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="4.0"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="#all"
  xmlns:ext="http://example.com/mf"
  extension-element-prefixes="ext"
  expand-text="yes">
  
  <xsl:template name="ext:sequence">
    <xsl:param name="select" as="item()*"/>
    <xsl:param name="separator" select="''"/>
    <xsl:for-each select="$select" separator="{{$separator}}">
      <xsl:sequence select="."/>
    </xsl:for-each>
  </xsl:template>

</xsl:stylesheet>,

$seq := ('a', 'b', <c/>, 'd', 'e', <f/>, <g/>,  'h')

return <e>{transform(map { 'stylesheet-node' : $xslt, 'initial-template' : QName('http://example.com/mf', 'sequence'), 'template-params' : map { QName('', 'select') : $seq }})?output}</e>

RE: Should fn:transform in SaxonCS support XSLT version 4? - Added by Michael Kay about 3 years ago

I'm pretty sure it's not something that we've tested.

RE: Should fn:transform in SaxonCS support XSLT version 4? - Added by Martin Honnen almost 3 years ago

Now with Saxon 11.1, I can run XQuery 4 calling fn:transform running XSLT 4, but it doesn't suffice to set the xqueryCompiler.setLanguageVersion("4.0"), I also have to enable syntax extensions on the processor (processor.setConfigurationProperty(Feature.ALLOW_SYNTAX_EXTENSIONS, true);), otherwise I get an error like "XTSE0020 Attribute xsl:for-each/@separator is allowed only if XSLT 4.0 is enabled".

Is that as intended/expected? Or shouldn't a request to run XQuery version 4.0 allow me to call fn:transform for XSLT version 4.0?

RE: Should fn:transform in SaxonCS support XSLT version 4? - Added by Michael Kay almost 3 years ago

I've added a specific test for both SaxonJ and SaxonCS that this works, and it's passing OK on the development branch - I don't know if I did anything to make it work, haven't tried running the test under 11.1 as issued.

    (1-5/5)

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