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How to call template xsl:initial-template with Python and SaxonC 11.1
Added by Martin Honnen almost 3 years ago
The API documentation of Python and SaxonC 11.1 suggests with https://www.saxonica.com/saxon-c/doc11/html/saxonc.html#PyXsltExecutable that the functions call_template_returning_X for the template name allow the use of None to "call the initial-template" (which I understand, means the XSLT 3 predefined xsl:initial-template).
However, my attempts to do so fail:
import saxonc
with saxonc.PySaxonProcessor(license=False) as proc:
print("Test SaxonC on Python")
print(proc.version)
xslt30proc = proc.new_xslt30_processor()
xslt30Executable = xslt30proc.compile_stylesheet(stylesheet_text = '''
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="3.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
expand-text="yes">
<xsl:output method="html" indent="yes" html-version="5"/>
<xsl:template match="/" name="xsl:initial-template">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Test</h1>
<ol>
<xsl:iterate select="1 to 5">
<li>Item {.}</li>
</xsl:iterate>
</ol>
</body>
</html>
<xsl:comment>Run with {system-property('xsl:product-name')} {system-property('xsl:product-version')} {system-property('Q{http://saxon.sf.net/}platform')}</xsl:comment>
</xsl:template>
</xsl:stylesheet>
''')
result = xslt30Executable.call_template_returning_string(None)
print(result)
outputs
Test SaxonC on Python
SaxonC-HE 11.1 from Saxonica
None
Is the documentation wrong or the Cython code needs to pass NULL instead of NONE to the C++ API to allow calling `xsl:initial-template?
Thanks for reporting this issue. Bug issue created #5274.
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RE: How to call template xsl:initial-template with Python and SaxonC 11.1
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Added by O'Neil Delpratt almost 3 years ago
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